So let the number we know nothing about ( B ) be X. We know that E has twice the coins that B has, so it would turn out to be
[tex]2x + x = 24 \\ 3x = 24 \\ \\ 24 \div3 = 8[/tex]
So B would be 8, but that's only one number. to find E, we need to get twice the amount that B has.
[tex]8 \times 2 = 16[/tex]
To check this answer, we need to see if 16 is twice 8, which it is, and if 8 + 16 = 24, which it does.
So E would be 16.
