Hey there!
[tex]\frac{2}{3} n[/tex] [tex]+ 8[/tex][tex]=\frac{1}{2} n[/tex] [tex]+2[/tex]
Firstly, we have to SUBTRACT by [tex]\frac{1}{2}n[/tex] on each of your SIDES
[tex]\frac{2}{3}n[/tex] [tex]+ 8[/tex] [tex]-[/tex][tex]\frac{1}{2}n[/tex] [tex]=[/tex][tex]\frac{1}{2} n[/tex][tex]+2[/tex][tex]-[/tex][tex]\frac{1}{2} n[/tex]
We get the result of ↓
[tex]\frac{1}{6}n[/tex] [tex]+ 8[/tex] [tex]= 2[/tex]
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Secondly we have to SUBTRACT by [tex]8[/tex] on each of your SIDES
[tex]\frac{1}{6} n+[/tex] [tex]8-8[/tex] [tex]= 2[/tex] [tex]-8[/tex]
[tex]2 -[/tex] [tex]8[/tex] [tex]= -[/tex][tex]6[/tex]
We get the result of ↓
[tex]\frac{1}{6} n[/tex] [tex]=-[/tex][tex]6[/tex]
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Thirdly, we have to MULTIPLY by [tex]6[/tex] on each of your SIDES
[tex]6[/tex][tex](\frac{1}{6}n)[/tex] [tex]=[/tex] [tex]6(-6)[/tex]
[tex]6(-6)[/tex] [tex]-36[/tex]
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ANSWER:
[tex]n[/tex] [tex]=[/tex] [tex]-36[/tex]
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Good luck on your assignment and enjoy your day!
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