abd is a right angled triangle so by pythagoras we know
[tex]{g}^{2} = {11}^{2} + {13}^{2} \\ {g}^{2} = 290 \\ g = \sqrt{290} \: or \: g = 17.03cm[/tex]
and to calculate h we need to use the sine rule
[tex] \frac{h}{ \sin(22) } = \frac{g}{ \sin(32) } \\ \frac{h}{ \sin(22) } = \frac{17.03}{ \sin(32) } \\ h = \frac{17.03}{ \sin(32) } \times \sin(22) \\ h = 12.04cm[/tex]
i hope this helps
