Let's assume
It started in 2000
so, t=0 in 2000
[tex]P_0=6.4million[/tex]
we can use formula
[tex]P(t)=P_0 e^{rt}[/tex]
we can plug value
[tex]P(t)=6.4 e^{rt}[/tex]
In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million
so, at t=2005-2000=5
P(t)=7.3 million
we can plug value and then we can solve for r
[tex]7.3=6.4 e^{r*5}[/tex]
[tex]r=0.02632[/tex]
now, we can plug back
[tex]P(t)=6.4 e^{0.02632t}[/tex]
now, we have
P(t)=1 billion =1000 million
so, we can set it and then we can solve for t
[tex]1000=6.4 e^{0.02632t}[/tex]
[tex]t=191.924[/tex]
approximately
[tex]t=192[/tex]
Year is 2000+192
year is 2192................Answer