The correct answer is D) x = 4 and x = -1
In order to solve this, we plug into the quadratic equation.
x = [tex]\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}[/tex]
In this case, a is the coefficient of x^2 (-1), b is the coefficient of x (3) and c is the constant (4). Now we plug in and solve.
x = [tex]\frac{-(3) +/- \sqrt{3^{2} - 4(-1)(4) } }{2(-1)}[/tex]
x = [tex]\frac{-3 +/- \sqrt{9 + 16 } }{-2}[/tex]
x = [tex]\frac{-3 +/- \sqrt{25 } }{-2}[/tex]
x = [tex]\frac{-3 +/- 5 } }{-2}[/tex]
And then we'll split into the two possible answers.
(-3 + -5)/-2 = -8/-2 = 4
(-3 - -5)/-2 = 2/-2 = -1
