[tex]Solution, solve\:for\:x,\:x^2-8x+7=0\quad :\quad x=7,\:x=1[/tex]
Steps:
[tex]Solve\:with\:the\:quadratic\:formula, \mathrm{For\:}\quad a=1,\:b=-8,\:c=7:\quad x_{1,\:2}=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:7}}{2\cdot \:1},\\[/tex]
[tex]x=\frac{-\left(-8\right)+\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:7}}{2\cdot \:1}:\quad 7[/tex]
[tex]x=\frac{-\left(-8\right)-\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:7}}{2\cdot \:1}:\quad 1[/tex][tex]\mathrm{The\:final\:solutions\:to\:the\:quadratic\:equation\:are:} x=7,\:x=1[/tex]
The correct answer is B.
