How to get answer by Mimiwhatsup:
[tex]3x^3+6x^2-24x\\\mathrm{Factor\:out\:common\:term\:}3x:\quad 3x\left(x^2+2x-8\right)\\3x^3+6x^2-24x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\x^3=x^2x\\=3x^2x+6xx-24x\\\mathrm{Rewrite\:}24\mathrm{\:as\:}3\cdot \:8\\\mathrm{Rewrite\:}6\mathrm{\:as\:}3\cdot \:2\\=3x^2x+3\cdot \:2xx-3\cdot \:8x\\\mathrm{Factor\:out\:common\:term\:}3x\\=3x\left(x^2+2x-8\right)\\\mathrm{Factor}\:x^2+2x-8:\quad \left(x-2\right)\left(x+4\right)\\x^2+2x-8\\Break\:the\:expression\:into\:groups\\[/tex]
[tex]=\left(x^2-2x\right)+\left(4x-8\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-2x\mathrm{:\quad }x\left(x-2\right)\\\mathrm{Factor\:out\:}4\mathrm{\:from\:}4x-8\mathrm{:\quad }4\left(x-2\right)\\=x\left(x-2\right)+4\left(x-2\right)\\\mathrm{Factor\:out\:common\:term\:}\left(x-2\right)\\=\left(x-2\right)\left(x+4\right)\\Answer: =3x\left(x-2\right)\left(x+4\right)[/tex]
A. Is the correct answer.
