[tex]\sqrt{75}\cdot\sqrt{12}=\sqrt{900}=30[/tex] so I believe none of the answers are applicable.
But if it is a "minus" [tex]\sqrt{75}-\sqrt{12}[/tex] then it can be written as
[tex]\sqrt{3\cdot25}-\sqrt{4\cdot3}=5\sqrt{3}-2\sqrt{3}=3\sqrt{3}[/tex]
and so that your answer