[tex]a=\dfrac{2d}{t^2}[/tex]
Find t as a function of d when a=5.
[tex]t^2 = \dfrac{2d}{a}[/tex]
[tex]t = \sqrt{\dfrac{2d}{a}}[/tex]
Substituting a=5,
[tex]t = \sqrt{\dfrac{2d}{5}}[/tex]
Choice D
