(x, y ) = (- 6, 3 )
Since both equations express y in terms of x, we can equate them
2x + 15 = - [tex]\frac{1}{3}[/tex] x + 1
( add [tex]\frac{1}{3}[/tex] x to both sides )
[tex]\frac{7}{3}[/tex] x + 15 = 1 ( subtract 15 from both sides )
[tex]\frac{7}{3}[/tex] x = - 14
( multiply both sides by 3 and divide by 7 )
x = ( 3 × - 14 )/7 = - 6
substitute x = - 6 into either of the 2 equations for y- coordinate )
y = ( 2 × - 6 ) + 15 = 3
solution : (x, y ) = ( - 6, 3 )
