When we multiply two powers of a common base, we add the exponents. That's the familiar rule
[tex]a^m a^n = a^{m+n}[/tex]
So here
[tex]13^8 \times 13 ^{-4} = 13^{8+ -4}= 13^4[/tex]
Answer: C
a^m a^n = a^{m+n}
13^8 \times 13 ^{-4} = 13^{8+ -4}= 13^4
