if a block is in equilibrium the magnitude of the block's acceleration is

The condition for an object to be in equilibrium is that there is no resulting force acting on it, in other words, that the force on the object is zero:

[tex]F=0[/tex]

and by Newton's second law we know that

[tex]F=ma[/tex]

where [tex]m[/tex] is the mass of the object, and [tex]a[/tex] its acceleration.

So combining the two things:

[tex]F=ma=0[/tex]

⇒[tex]ma=0[/tex], This equation is fulfilled when [tex]a=0[/tex]

Wich tells us that for the the block to be in equilibrium, the acceleration must be zero:

[tex]a=0[/tex]

abidemiokin abidemiokin · Answer 2 · 2021-10-25T17:09:28+02:00

If a block is in equilibrium the magnitude of the block's acceleration is 0m/s²

According to Newton's second law, the force acting on a body is equal to the product of its mass and acceleration.

Mathematically F = ma where:

m is the mass of the object

a is the acceleration of the object

If a block is in equilibrium, the magnitude of the force acting on the block will be 0, that is F = 0

Substituting F = 0 into the formula above to calculate the acceleration;

F = ma

0 = ma

Swap sides

ma = 0

a =0/m

a = 0m/s²

This shows that if a block is in equilibrium the magnitude of the block's acceleration is 0m/s²

Learn more here: https://brainly.com/question/17811936