help please 4, 5, 6.......
4. Supplementary angles together make a straight line (two right angles). So BOE is supplementary to BOC
Answer: ∠BOE
5. Distance and midpoint between (4,-2), (6,8)
[tex]d = \sqrt{ (6-4)^2 + (8 - -2)^2} = \sqrt{2^2+10^2}=\sqrt{104}=2 \sqrt{26}[/tex]
midpoint
[tex]\left(\dfrac{4 + 6}{2}, \dfrac{-2 + 8}{2} \right) = (5, 3)[/tex]
Answer: distance 2√26, midpoint (5, 3)
6.That's a rectangle oriented parallel to the axes, width parallel to the x axis of 7 - -3 = 10 and length along y of 1 - - 4 = 5, so an area of 10(5)=50
Answer: 50