Siobha
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Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

Can someone explain this differentiation question to me I can differentiate but then Im not sure what I am doing class=

Respuesta :

note that gradient = [tex]\frac{dy}{dx}[/tex] at x = a

calculate [tex]\frac{dy}{dx}[/tex] for each pair of functions and compare gradient

(a)

[tex]\frac{dy}{dx}[/tex] = 2x and [tex]\frac{dy}{dx}[/tex] = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)

[tex]\frac{dy}{dx}[/tex] = 2x + 3 and [tex]\frac{dy}{dx}[/tex] = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)

[tex]\frac{dy}{dx}[/tex] = 4x + 13 and [tex]\frac{dy}{dx}[/tex] = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)

[tex]\frac{dy}{dx}[/tex] = 6x - 5 and [tex]\frac{dy}{dx}[/tex] = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x = [tex]x^{\frac{1}{2} }[/tex]

[tex]\frac{dy}{dx}[/tex] = 1/(2√x) and [tex]\frac{dy}{dx}[/tex] = 2

at x = 9 : gradient = [tex]\frac{1}{6}[/tex] and 2 and 2 > [tex]\frac{1}{6}[/tex]


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