Respuesta :
Answer:
Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, [tex]Speed = \frac{Distance}{Time}[/tex]
So, the speed of Pratap with the current will be: [tex](\frac{10}{2})miles/hour = 5[/tex] miles/hour
and the speed of Pratap against the current will be: [tex](\frac{10}{2.5})miles/hour = 4[/tex] miles/hour.
Suppose, the rate of Pratap in still water is [tex]x[/tex] and the rate of current is [tex]y[/tex].
So, the equations will be........
[tex]x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)[/tex]
Adding equation (1) and (2) , we will get......
[tex]2x=9\\ \\ x=\frac{9}{2}= 4.5[/tex]
Now, plugging this [tex]x=4.5[/tex] into equation (1), we will get.....
[tex]4.5+y=5\\ \\ y=5-4.5 =0.5[/tex]
Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
