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If 18.0 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia? Express your answer with the appropriate units.

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organicstars801

Answer:

  • The molarity of ammonia will be 2.88 M.

Chemical equation

                                      HCl +  NH3 ------> NH4Cl

First of calculate the moles of HCl

mole of HCl = Molarity × Vol (L)

mole of HCl = 0.800× 0.018 = 0.014 mole

As the in balance chemical, moles of HCl and NH3 areequal

so

                        moles of NH3= 0.014

                       Molarity of NH3 = moles ÷ V(L) = 0.014/0.005 =  2.88 M

Result:

  • The molarity of ammonia will be 2.88 M.

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