The algebraic expression to represent this situation is : [tex]11(3a+2b+c+2d)[/tex]
Explanation
Suppose, the cost of a uniform is [tex]a[/tex] , cost of a shin guard is [tex]b[/tex] , cost of a ball is [tex]c[/tex] and cost of a pair of cleat is [tex]d[/tex]
Each player needs three uniforms,two shin guards,one ball,and two pairs of cleats. So, the total cost for one player [tex]= 3a+2b+c+2d[/tex]
Thus, the total cost for 11 players will be: [tex]11(3a+2b+c+2d)[/tex]
