Total sum of angles of a triangle is equal to 180 degrees.
First angle = 4x-3 degrees.
Second angle = 6x-6 degrees.
Let the third angle be represented by [tex]\beta[/tex]
[tex]4x-3 + 6x-6 +\beta =180[/tex]
Add all the terms with x together and all the constants together.
[tex](4x+6x) + ( -3 -6 ) + \beta = 180[/tex]
[tex]10x -9 +\beta = 180[/tex]
[tex]\beta = 180 - 10x+ 9[/tex]
Third angle [tex]\beta = 189 -10x[/tex] .... Answer
