Given expression is 35, 36, 37, 38...
First term a = 35
Common difference d = 36-35 = 1
Nth term of arithmetic sequence is:
[tex]n_{th} = a+ (n-1)d[/tex]
[tex]n_{th}= 35+(n-1)(1)[/tex]
[tex]n_{th} = 34+n[/tex]
To find the 100th term, substitute n = 100
[tex]n_{100} = 34 +100[/tex]
[tex]n_{100} =134[/tex]
Correct option is B
