Step [tex]1[/tex]
we know that
The density's formula is equal to
[tex]density=\frac{mass}{volume}[/tex]
The volume of a cone is equal to
[tex]Volume=\frac{1}{3}\pi r^{2} h[/tex]
where
r is the radius of the base of the cone
h is the height of the cone
in this problem
[tex]r=5cm\\ h=2 cm[/tex]
substitute the values in the formula above
[tex]Volume=\frac{1}{3}*\pi*5^{2}*2[/tex]
[tex]Volume=52.36\ cm^{3}[/tex]
Step [tex]2[/tex]
Find the density
we have
[tex]Volume=52.36\ cm^{3}[/tex]
[tex]mass=6\ g[/tex]
substitute in the formula
[tex]density=\frac{mass}{volume}[/tex]
[tex]density=\frac{6}{52.36}[/tex]
[tex]density=0.11\frac{g}{cm^{3} }[/tex]
therefore
the answer is
the density is [tex]0.11\frac{g}{cm^{3} }[/tex]
