A cylindrical water tower has a height of 6 ft and a radius of 4 ft. How much water does the tower contain when it is 1/3 full? Approximate π as 3.14. Round your answer to the nearest tenth.

Respuesta :


[tex]\pi r ^{2} \times h[/tex]

Answer:

Water contains in the cylindrical water tower is 100.48 ft³ .

Step-by-step explanation:

Formula

[tex]Volume\ of\ a\ cylinder = \pi r^{2} h[/tex]

Where r is the radius and h is the height .

As given

A cylindrical water tower has a height of 6 ft and a radius of 4 ft.

π = 3.14

Putting all the values in the formula

[tex]Volume\ of\ a\ cylinderical\ water\ tower =3.14\times 4\times 4\times 6[/tex]

[tex]Volume\ of\ a\ cylinderical\ water\ tower =301.44\ ft^{3}[/tex]

As given

[tex]Tower\ contain\ water\ it\ is\ \frac{1}{3}\ full.[/tex]

Thus

[tex]Water\ contain\ in\ cylindrical\ tower = \frac{1}{3}\times Volume\ of\ cylindrical\ water\ tower[/tex]

Putting values in the above

[tex]Water\ contain\ in\ cylindrical\ tower = \frac{1\times 301.44}{3}[/tex]

                                                                    = 100.48 ft³

Therefore the water contains in the cylindrical water tower is 100.48 ft³ .

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