we are given
[tex] \frac{t^2-4t-32}{t-8} [/tex]
we know that
denominator of any expression can not be zero
so,
[tex] t-8 \neq 0 [/tex]
[tex] t \neq 8 [/tex]
so, this is restriction
now, we will factor numerator
[tex] \frac{t^2-4t-32}{t-8}= \frac{(t-8)(t+4)}{t-8} [/tex]
now, we can simplify it
[tex] \frac{t^2-4t-32}{t-8}= (t+4) [/tex]
so, option-C............Answer
