Answer:
[tex]\large\boxed{\dfrac{-2\cdot3+12}{(5-3)^2}=\dfrac{3}{2}}[/tex]
Step-by-step explanation:
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
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[tex]\dfrac{-2\cdot3+12}{(5-3)^2}=\dfrac{-6+12}{2^2}=\dfrac{6}{4}=\dfrac{6:2}{4:2}=\dfrac{3}{2}[/tex]
