Respuesta :
Answer:
The efficiency of the engine is 47%.
Explanation:
Given that,
Cold reservoir[tex]T_{1} = 250^{\circ}\ C[/tex]
[tex]T_{1}=250+273=523\ K[/tex]
Hot reservoir [tex]T_{2} = 715^{\circ}\ C[/tex]
[tex]T_{2}=715+273=988\ k[/tex]
The formula efficiency of the engine is defined as:
[tex]\eta =\dfrac{T_{2}-T_{1}}{T_{2}}[/tex]
[tex]\eta =1-\dfrac{T_{1}}{T_{2}}\times100[/tex]
We substitute the value into formula
[tex]\eta =1-\dfrac{523}{988}\times100[/tex]
[tex]\eta = 47\%[/tex]
Hence, The efficiency of the engine is 47%.
