The vertex form will be: [tex] y=9(x-0)^2 -1 [/tex]
Explanation
The vertex form of any quadratic is : [tex] y= a(x-h)^2 +k [/tex] where [tex] (h,k) [/tex] is the vertex point.
Given equation is : [tex] y= 9x^2 -1 [/tex]
[tex] x^2 [/tex] can be rewritten as [tex] (x)^2 [/tex] or [tex] (x-0)^2 [/tex]
Thus,
[tex] y=9x^2-1\\\\ y=9(x-0)^2 -1 [/tex]
This equation is in form of [tex] y= a(x-h)^2 +k [/tex]
So, the vertex form will be: [tex] y=9(x-0)^2 -1 [/tex]