Time taken to reach the ground is given by vertical direction
[tex]y = v_y * t + \frac{1}{2}gt^2[/tex]
[tex]0.15 = 0 + \frac{1}{2}*9.8*t^2[/tex]
[tex]t = 0.175 s[/tex]
now in the same time it will move horizontally
[tex]d = v_x * t[/tex]
[tex]d = 10 * 0.175 = 1.75 m[/tex]
so it will land at distance 1.75 m
