The total amount In cups of dry goods that tanner could store in all three containers is; 26¹¹/₁₂ cups
We are told that;
Quantity of container A; 12³/₄ cups of dry goods = ⁵¹/₄ cups of dry goods
Quantity of container B; ²/₃ * container A = ²/₃ * 12³/₄ = ⁵¹/₆ cups of dry goods
Quantity of container C; ²/₃ * container B = ²/₃ * ⁵¹/₆ = ⁵¹/₉ cups of dry goods
Thus;
Total amount in cups of dry goods that could be stored in all 3 containers is; ⁵¹/₄ + ⁵¹/₆ + ⁵¹/₉ = 323/12
⇒ 26¹¹/₁₂ cups
Read more about Addition of Fractions at; https://brainly.com/question/11562149