According to Henry's law, solubility of solution is directly proportional to partial pressure thus,
[tex]\frac{S_{1}}{P_{1}}=\frac{S_{2}}{P_{2}}[/tex]
Solubility at pressure 3.08 atm is 72.5/100, solubility at pressure 8 atm should be calculated.
Putting the values in equation:
[tex]\frac{0.725}{3.08}=\frac{S_{2}}{8}[/tex]
On rearranging,
[tex]S_{2}=\frac{0.725\times 8}{3.08}=1.88[/tex]
Therefore, solubility will be 1.88 mg of [tex]N_{2}[/tex] gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.
