Respuesta :
Average Speed
Jack swims nine lengths of a 25 meter long swimming pool in 2 minutes and 32.1 seconds.
So, total distance [tex]=(25*9)meters= 225 meters[/tex] and time [tex]=(60*2+32.1)seconds=152.1 seconds[/tex]
Thus, average speed of Jack [tex]=\frac{Distance}{Time}=\frac{225}{152.1}meters/second=1.4792...meters/second[/tex]
Now, Jill swims ten lengths of the 25 meter long swimming pool in the same time interval.
So, the total distance [tex]=(25*10)meters=250 meters[/tex] and time [tex]=152.1 seconds[/tex]
Thus, average speed of Jill [tex]=\frac{Distance}{time}=\frac{250}{152.1} meters/second=1.6436...meters/second[/tex]
Average Velocity
As Jack swims nine lengths of the pool, it means he ends up at the opposite end of the pool from where he started. So, the net displacement = 25 meter
Thus, average velocity of Jack [tex]=\frac{Displacement}{Time}=\frac{25}{152.1} meters/second=0.1643...meters/second[/tex]
Now, Jill swims ten length of the pool, it means he ends up at the starting position. So, the net displacement = 0 meter
Thus, average velocity of Jill [tex]=\frac{Displacement}{Time}=\frac{0}{152.1}meter/second= 0[/tex] meter/second.
