Let volumetric size of a water molecule = v
Since, 1 mole of water consists of [tex]6.023\times 10^{23}[/tex] molecules of water.
Thus, total volume of 1 mole of water = [tex]volumetric size \times 6.023\times 10^{23}[/tex]
Substitute the value of total volume of 1 mole of water i.e. 22.4 L in above formula.
[tex]22.4 L = v\times 6.023\times 10^{23}[/tex]
[tex]v= \frac{22.4 L}{6.023\times 10^{23}}[/tex]
Convert the unit litre to angstrom
[tex]v=\frac{22.4 L}{6.023\times 10^{23}}\times \frac{1dm^{3}}{1L}\times \frac{(10^{9})^{3}(A^{o})^{3}}{1 dm^{3}}[/tex]
= [tex]3.7\times 10^{-23}\times 10^{27} (A^{o})^{3}[/tex]
= [tex]3.7 \times 10^{4}(A^{o})^{3}[/tex]
Therefore, the volumetric size of the water molecule is [tex]3.7 \times 10^{4}(A^{o})^{3}[/tex]
