Answer:
9.4 × 10⁻¹² g of NH₃
Solution:
Step 1: Calculate Number of NH₃ Molecules containing 1 Trillion Hydrogen Atoms:
As,
3 Hydrogen Atoms are present in = 1 Molecule of NH₃
So,
1 × 10¹² Hydrogen Atoms will be present in = X Molecules of NH₃
Solving for X,
X = (1 × 10¹² × 1) ÷ 3
X = 3.33 × 10¹¹ Molecules of NH₃
Step 2: Calculate Moles of NH₃:
As,
Moles = Number of Molecules ÷ 6.022 × 10²³
Putting value,
Moles = 3.33 × 10¹¹ Molecules ÷ 6.022 × 10²³
Moles = 5.53 × 10⁻¹³ mol
Step 3: Calculate Mass of NH₃:
As,
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 5.53 × 10⁻¹³ mol × 17 g.mol⁻¹
Mass = 9.4 × 10⁻¹² g of NH₃
