Answer is 54 °C.
Explanation;
We can simply use heat equation
Q = mcΔT
Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Let's assume that the initial temperature is T.
Q = 5.53 × 10⁵ J
m = 2850 g
c = 4.186 J/g °C
ΔT = (100 - T) °C Since the water is boiling, the final temperature is 100 °C.
By applying the equation,
5.53 × 10⁵ J = 2850 g x 4.186 J/g °C x (100 - T) °C
(100 - T) °C = 5.53 × 10⁵ J / (2850 g x 4.186 J/g °C )
(100 - T) °C = 46.35 °C
T = 100 - 46.35 C = 53.65 °C
≈ 54 °C
