Respuesta :
Experimental molar mass = 48.45 g/mol. Actual molar mass = 52.98 g/mol. Error in molar mass= (52.98-48.45) = 4.53. Percentage error in molar mass= (Error in molar mass)/Actual molar mass = (4.53/52.98)X100= 8.55 %. The formula utilised here is percentage error= (Exact value - Approximate value)X100/Exact value. First approximate value is to be subtracted from exact value, then divide the number by exact value. Finally, the fraction is to be multiplied by 100 to get percentage error.
Answer: The percentage error is 8.55 %.
Explanation:
To calculate the percentage error, we use the equation:
[tex]\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100[/tex]
We are given:
Experimental value of molar mass = 48.45 g/mole
Accepted value of molar mass = 52.98 g/mole
Putting values in above equation, we get:
[tex]\%\text{ error}=\frac{|48.45-52.98|}{52.98}\times 100\\\\\%\text{ error}=8.55\%[/tex]
Hence, the percentage error is 8.55 %.
