Let the beam is of length L
Now the stress on both the end is same
now we can say that torque on the beam due to two forces must be zero
[tex]N_1* x = N_2* (L - x)[/tex]
also we know that stress at both ends are same
[tex]\frac{N_1}{12} = \frac{N_2}{8}[/tex]
[tex]2*N_1 = 3*N_2[/tex]
Now from two equations we have
[tex]\frac{3}{2}N_2*x = N_2* (L - x)[/tex]
solving above equation we have
[tex]x = \frac{2}{5}L[/tex]
so the load is placed at distance 0.4L from the end of 12 mm^2 area
