The length of a rectangle is 3 meters less than twice the width. If the area of the rectangle is 209 square​ meters, find the dimensions.

Respuesta :

Length: 2w - 3

width: w

Area (A) = L x w

     209  = (2w - 3)w

     209 = 2w² - 3w

         0 = 2w² - 3w - 209

         0 = (2w + 19)(w - 11)

0 = 2w + 19       0 = w - 11

w = -19/2             w = 11

Since width cannot be negative, disregard -19/2

w = 11

Length: 2w - 3  = 2(11) - 3   = 22 - 3   = 19

Answer: width = 11 meters, length = 19 meters

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