For any temperature scale the ratio of difference of temperature will be same
so we can write
[tex]\frac{T^ox - 12^ox}{129^ox - 12^ox} = \frac{T^of - 32^of}{212^of - 32^of}[/tex]
now given that in both scales the temperature must be same
[tex]\frac{T^ox - 12^ox}{117^ox} = \frac{T^of - 32^of}{180^of}[/tex]
[tex]T - 12 = 0.65 (T - 32)[/tex]
[tex]0.35T = -8.8[/tex]
[tex]T = -25.14 ^ox[/tex]
so at above temperature both scales will have same temperature