Answer:
Ethanol = 102.29 g
Carbon Dioxide = 97.71 g
Solution:
The Balance Chemical Equation for the fermentation of Glucose is as follow,
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
Mass of Ethanol produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 92.14 g (2 moles) of C₂H₅OH
So,
200 g of C₆H₁₂O₆ will produces = X g of C₂H₅OH
Solving for X,
X = (200 g × 92.14 g) ÷ 180.156 g
X = 102.29 g of C₂H₅OH
Mass of Carbon Dioxide produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 88.02 g (2 moles) of CO₂
So,
200 g of C₆H₁₂O₆ will produces = X g of CO₂
Solving for X,
X = (200 g × 88.02 g) ÷ 180.156 g
X = 97.71 g of CO₂
