For this case, the first thing we must do is define variables.
We have then:
t: number of hours
F (t): total charge
We write the function that models the problem:
[tex] F (t) = 6t + b [/tex]
Where,
b: represents an initial fee.
We must find the value of b.
For this, we use the following data:
Her total fee for a 4-hour job, for instance, is $ 32.
We have then:
[tex] 32 = 6 (4) + b [/tex]
From here, we clear the value of b:
[tex] 32 = 24 + b [/tex]
[tex] 32-24 = b [/tex]
[tex] b = 8 [/tex]
Then, the function that models the problem is:
[tex] F (t) = 6t + 8 [/tex]
Answer:
the function's formula is:
[tex] F (t) = 6t + 8 [/tex]
