Amount of heat for melting the ice.
Q_1 = mL
Where m is mass
L is latent heat of ice
S is specific heat
[tex]= 185 (80) = 14800 cal[/tex]
Amount of heat for rising the temperature of ice to 37 C^0.
[tex]For 0 C^0 to 37 C^0[/tex]
[tex]Q_2 = m s dT[/tex]
[tex]= 185 (540) (37) = 3696.3 * 10^3 cal[/tex]
Q = Q1 + Q2
[tex]= 14800 + 3696.3 * 10^3 = 3711.11 * 10^3 cal[/tex]
Thus, 3711.11 * 10^3 cal of energy is required for reaching the temperature of ice to 37 C^0
