Respuesta :
Volume of an iceberg = 7685 cubic feet
Since, density of ice = 0.917 [tex]g/cm^3[/tex]
We have to determine the mass of the ice.
Since density = [tex]mass \times volume[/tex]
Since the unit of density is in [tex]g/cm^3[/tex], first we will convert the density unit in kilogram.
Since, 1 kilogram = 1000 gram
Therefore, density = [tex]\frac{0.917}{1000} kg/cm^3[/tex]
= 0.000917 [tex]kg/cm^3[/tex]
Since, the density unit is in cubic centimeter. We will convert it into cubic feet.
1 cubic centimeter = 0.00003531466 cubic feet
Therefore, 0.000917 [tex]kg/cm^3[/tex] = 0.000917 x 0.00003531466
= 0.0000000323 [tex]kg/ft^3[/tex].
Now, mass = [tex]density \times volume[/tex]
= 0.0000000323 [tex]\times[/tex] 7685
= 0.000248
=0.00025 [tex]kg[/tex].
Therefore, the mass of ice is 0.00025 [tex]kg[/tex].
Answer:
199,552.74 kg
Step-by-step explanation:
The density of ice is 917 kg/m³. The density of an object is defined as the ratio of the mass of the object to the volume of the object.
Given that the volume of the ice is 7685 cubic feet and we known that
1 m³ = 35.3147 cubic feet
Therefore 7685 cubic feet
= 7685/35.3147
= 217.614761 m³
Since Density = mass/vloume
mass = density * volume
= 917 kg/m³ * 217.614761 m³
= 199,552.7358
≈ 199,552.74 kg
