It is given in the question that
A new youth sports center is being built in oak valley. The perimeter of the rectangular playing field is 522 yards. The length of the field is 4 yards less than quadruple the width.
Let the width be x yards . And the length is 4 yards less than 4times the width .
So length is
[tex](4x-4) yards[/tex]
And the perimeter is the sum of all sides, that is
[tex]x+4x-4+x+4x-4+x = 522[/tex]
Combining the like terms,
[tex]10x -8 = 522[/tex]
Adding 8 to both sides
[tex]10x=530 \\ x = 53 yards[/tex]
Therefore the width is 53 yards, and length is 4 less than 4 times the width, that is
[tex]4*53-4 = 208 yards[/tex]
