It is given in the question that
The perimeter of the rectangular playing field is 564 yards. The length of the field is 8 yards less than quadruple the width.
Let the width be x yards. SO length is
[tex]=(4x-8) yards[/tex]
And perimeter is the sum of all sides. That is
[tex]x+4x-8+x+4x-8 = 564
\\
10x -16= 564
\\
10x = 580
\\
x=58[/tex]
Therefore the width is 58 yards. And the length is
[tex]= 4(58)-8 = 224 yards[/tex]
