This is a problem of inequalities. An inequality stands for the relationship between two values when they are different. In this problem, we need to solve for x. So, we have that:
[tex] -ax+3b>5 [/tex]
Subtracting 3b from each side of the equation, we have:
[tex] -ax+3b \mathbf{-3b}>5 \mathbf{-3b} \\ \\ -ax>5-3b [/tex]
Multiplying by [tex]-\frac{1}{a}[/tex] the direction of the inequality changes if [tex]a[/tex] is greater than zero, so we have that solving for x the result is:
[tex] -\frac{1}{a}(-ax)<-\frac{1}{a}(5-3b) \\ \\ x<\frac{3b-5}{a} [/tex]