We'll use the Pythagorean Theorem (otherwise known as the Distance Formula):
Going from Q to P, x increases by 1 and y increases by 7. Thus, the component form of QP is <1,7>, and the magnitude of this vector is √(1^2+7^2) = 5√2.
Note: this is equivalent to <1, 7>, square root of 50.
Answer with explanation:
P=(-5,11)=-5 i +11 j
Q=(-6,4)= -6 i+ 4 j
⇒Component of Vector QP
=Position vector of P -Position vector of Q
= -5 i + 11 j - (-6 i+4 j)
= -5 i +11 j +6 i -4 j
= i +7 j------------Adding like terms
⇒Magnitude of vector QP
[tex]=\sqrt{(1)^2+(7)^2}\\\\=\sqrt{50}[/tex]
Option D
