Respuesta :

altavistard

Especially if we're to present the answers to 2 decimal places, we'd gues that the roots of this polynomial are not "nice."

My suggestion is that we use the quadratic formula to find the roots, and then write the associated factors.

In 3x^2 +x-5=0, a=3, b=1 and c= -5. Thus, the roots are

-1 plus or minus √(1^2 - 4(3)(-5) )

x = --------------------------------------------------

2(3)

or:

-1 plus or minus √61 -1 plus or minus 7.81

x = ----------------------------------- = ---------------------------------

6 6

Then one root is 6.81/6, or approx. 1.14, and the other is

-8.81/6, or approx. -1.47.

The solution set is then {-1.47, 1.14}.

onyebuchinnaji

The value of x is 1.14 or -1.47

The given equation;

[tex]3x^2 + x - 5 = 0[/tex]

We will solve the given quadratic equation using formula method;

a = 3, b = 1, c = -5

[tex]x = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a}[/tex]

Substitute the given values of a, b, and c, to solve for x;

[tex]x = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-1 \ \ +/- \ \ \sqrt{(1)^2 - 4(3\times -5)} }{2(3)} \\\\x = \frac{-1 \ \ +/- \ \ \sqrt{61} }{6} \\\\x = \frac{-1 \ \ +/- \ \ 7.81}{6} \\\\x = \frac{-1 + 7.81 }{6} \ \ or \ \frac{-1 -7.81}{6} \\\\x = 1.14 \ \ or \ \ -1.47[/tex]

Thus, the value of x is 1.14 or -1.47

Learn more here: https://brainly.com/question/18162688

Otras preguntas

Q&A Education