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Every one reading this please help! I don't understand this and I will give brainliest to the person that helps first with a good explanation. This is the question: a rectangular poster is 32 inches long by 24 inches wide. It Will be put into a rectangular frame that is 2 inches wide on all sides. What is the ares of the poster when it is inside the frame?

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sqdancefan
Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.

The length of the poster in its frame is ...
  (frame width on one side) + (poster length) + (frame width on the other side)
  2 in + 32 in + 2 in = 36 in

Likewise, the width of the poster in its frame is ...
  2 in + 24 in + 2 in = 28 in

The area of a rectangle 36 in by 28 in is the product of these dimensions:
  Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
2020bmac
So you have a poster of 32 in. by 24 in. and then you will add 2 in. to each. 
Then you will have 34 in. by 26 in.
Multiply 34 and 26 to get 884 as your area. And I believe that wold be considered 884 sq. in.
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