yvictoria16 yvictoria16

05-07-2018
Mathematics

contestada

Someone help me please I don't know how to do this ! :(

Someone help me please I dont know how to do this class=

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konrad509 konrad509

05-07-2018

[tex]4^{x+1}=21\\ x+1=\log_421\\ x=\log_421-1\\ x=\log_421-\log_44\\ x=\log_4\dfrac{21}{4}\\ x=\dfrac{\ln \dfrac{21}{4}}{\ln 4}\approx 1.1962[/tex]

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