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Line CD passes through points C(1, 3) and D(4, –3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
–5
–2
1
5

Respuesta :

3ricaaa
The value of b is 5.

Find the slope (m)of the points first and you'll get -6/3, which is -2.
Choose a point and the -2 and plug the values into the formula y=mx + b to find b.
3 = -2 (1) + b
3 = -2 + b
+2 = +2 +b
5 = b

Answer:

5

Step-by-step explanation:

Since, the equation of the line passes through [tex](x_1,y_1)[/tex] and [tex](x_2, y_2)[/tex] is,

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Thus, the equation of the line passes through points C(1, 3) and D(4, -3) is,

[tex]y-3=\frac{-3-3}{4-1}(x-1)[/tex]

[tex]y-3=-\frac{6}{3}(x-1)=-2(x-1)=-2x+2[/tex]

[tex]y=-2x+2+3[/tex]

[tex]\implies y =-2x+5[/tex]

Now, the slope-intercept form of line is, y = mx + b,

By comparing,

b = 5

LAST option is correct.

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