bayleecase2002
bayleecase2002
05-07-2018
Mathematics
contestada
Help please?? 50 points!
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Summer0822
Summer0822
05-07-2018
[tex]6 \sqrt{3} [/tex]
is the correct answer
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gmany
gmany
05-07-2018
The triangle ABC and the triangle BCD are similar, therefore
[tex]\dfrac{3+9}{x}=\dfrac{x}{9}\ \ \ |cross\ multiply\\\\x^2=12\cdot9\\\\x^2=108\to x=\sqrt{108}\\\\x=\sqrt{36\cdot3}\\\\x=\sqrt{36}\cdot\sqrt3\\\\\boxed{x=6\sqrt3}[/tex]
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