Answer:
A. y = -2 - cos(x-π)
Explanation:
The general form of the trig equation is:
y = A sin (Bx + C) + D
where:
A is the amplitude
[tex] \frac{2\pi}{B} [/tex] is the period
[tex] \frac{-C}{B} [/tex] is the phase shift
D is the vertical shift
Now, let's check the choices:
A. y = -2 - cos(x-π)
[tex] \frac{-C}{B} = \frac{\pi}{1} = \pi [/tex]
Therefore, the function has a phase shift of π
B. y = 3 cos(4x)
[tex] \frac{-C}{B} = \frac{0}{4} = 0 [/tex]
Therefore, the function has no phase shift
C. y = tan(2x)
[tex] \frac{-C}{B} = \frac{0}{2} = 0 [/tex]
Therefore, the function has no phase shift
D. y = 1 + sin(x)
[tex] \frac{-C}{B} = \frac{0}{1} = 0 [/tex]
Therefore, the function has no phase shift
Based on the above, the correct answer is A
Hope this helps :)
